Question

if 3+4=11
4+8=19
5+36=31
then 7+25=?

Answer 1

Correct Question:

If 3 + 4 = 11

4 + 9 = 19

5 + 36 = 31

Then, 7 + 25 = ?

Answer

7 + 25 = 54

$\rule{200}2$

Solution

3 + 4 = 7. But given that, sum of three and four is 11.

Now, Subtract 7 from 11. On subtracting we get, 4.

Similarly, 4 + 9 = 13. On subtracting 13 from 19 we get, 6.

Difference of both of them is different.

$\rule{100}1$

3 + 4 = 11

Now, take square of first number. (3)²= 9.

11 - 9 = 2. If we take square root of four we get two and on addition we get eleven.

(Square of first number) + (Square root of second number)

→ (3)² + √4 = 9 + 2 = 11

Similarly,

→ (4)² + √9 = 16 + 3 = 19

→ (5)² + √36 = 25 + 6 = 31

Now, we have to find the sum of 7 and 25. Apply the same formula on it. Do square of first number. i.e. 7 and square root of second number i.e. 25.

→ (7)² + √25 = 49 + 5 = 54

Answer 2

||✪✪ CORRECT QUESTION ✪✪||

if

→ 3 + 4 = 11

→ 4 + 9 = 19

→ 5 + 36 = 31

Then,

→ 7 + 25 = ?

|| ✰✰ ANSWER ✰✰ ||

Logic :- (First Number)² + √(second Number).

Check :-

→ 3 + 4 = 11 => (3)² + √(4) = 9 + 2 = 11 .

→ 4 + 9 = 19 => (4)² + √(9) = 16 + 3 = 19.

→ 5 + 36 = => (5)² + √(36) = 25 + 6 = 31 .

So, we can say That :-

→ 7 + 25 = (7)² + √(25) = 49 + 5 = 54 (Ans).