Question

if 3 and -3 are the two zeros of the polymomial P(x)=x4+x3-11x2-9x+18,then find the remaimng tow polymamial​

Answer 1

Explanation:

$p(x) = {x}^{4} - {x}^{3} - 11 {x}^{2} - 9x + 18 \\ \\putting \: x = 3 \\ \\ p(3) = {3}^{4} - {3}^{3} - 11( {3})^{2} - 9 \times 3 + 18 \\ \\ = 81 - 27 - 99 - 27 + 18 \\ \\ = - 54 \\ \\ putting \: ( - 3) \\ \\ p( - 3) = {( - 3)}^{4} - {( - 3)}^{3} - 11 {( - 3)}^{2} - 9 \times ( - 3) + 18 \\ \\ = 81 + 27 - 99 + 27 + 18 \\ \\ = 51$