Question

if 3 cos A - 4sin A = 2cos A + sin A, find tan A

Answer 1

3×B/H-4×P/H=2×B/H+P/H Taking lcm 3B-4P/H=2B+P/H 3B-4P/2B+P=1 3B-4P=2B+P B=5P P=5/B PUT VALUE OF B P=1/P P=1 B=5 tan=P/B =1/5

Answer 2

3 cosA - 4 SinA = 2 CosA + SinA 

3 cosA - 4 SinA - ( 2 CosA + SinA ) = 0
Opening the bracket ,

3 cosA - 4 SinA - 2 CosA - SinA  = 0
CosA - 5 SinA = 0

÷ every term by cosA
∴ 1 - 5 [ SinA / CosA ] = 0
We  know, 
         Sinθ / Cosθ = Tanθ
∴ 1 - 5 tanA = 0
   1 = 5 tanA
So, Tan A = 1/5 //