if 3 is the root of a quadratic equation x^2+px+9=0 and quadratic equation x^2+px+k=0 has equal roots then find k
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(3)2+P3+9=0
9+3p+9=0
18+3p
3p=-18
P=-6
(3)2-6*3+k=0
9-18+k=0
k=9
9+3p+9=0
18+3p
3p=-18
P=-6
(3)2-6*3+k=0
9-18+k=0
k=9
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5
k=9 is the answer of above question
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