Question

if 3 resistors of 2 Ω are connected in parallel then the net Resistance will be?
Hint - Parallel resistance = 1/R(net) = (1/R_1)+(1/R_2)....​

Answer 1

Here

R1 = 2Ω

R2 = 2Ω

R3 = 2Ω

1/R(net) = (1/R_1)+(1/R_2)+(1/R_3)

1/R(net) = 1/2 + 1/2 + 1/2

1/R(net) = 3/2Ω

R(net) = 2/3Ω

Answer 2

1/R=(1/R1)+(1/R2)

Hence effective resistance=1/(1/R)

In case the resistances are equal, then effective resistance in parallel is: R/N, where R is the value of resistance and N is the no of resistors in parallel.

Now, as per your question, effective resistance is: R=2ohms; N=2 resistors in parallel. Hence, 2ohms/2 resistors in parallel= 1 ohm effective.

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