Math, asked by AsifAhamed4, 1 year ago

if √3 sin Φ- cos Φ=0 find the value of Φ.

please help me out to solve this questions.

the person who explains step by step will get the brainliest answer

Answers

Answered by Anonymous
4
(√3sinA - cosa)=0

√(3^2+1^2)=2

=> 2(√3/2sina -1/2cosa)=0

We know that √3/2=cos30°
and 1/2=sin30°

so ....

2(cos30°sinA- sin30°cosA)=0

We know that cos@sinB - sin@cosB
= sin(B-@)

so....
2sin(A-30°)=0

=> sin(A-30°)=0

=> sin(A-30°)=sin(nπ)

=> A-30°=nπ

=> A=nπ +30°


Where n is an Integer (belongs to Z)
Similar questions