if √3 tan theta =1 and theta is acute angle find the value sin theta and costheta
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Answer :
• sinθ = 1/2
• cosθ = √3/2
Solution :
- Given : √3•tanθ = 1 , 0 < θ < 90°
- To find : sinθ , cosθ = ?
We have ;
=> √3•tanθ = 1
=> tanθ = 1/√3
Also ,
We know that ,
tanθ = p/b
Thus ,
tanθ = p/b = 1/√3
Clearly ,
p = 1
b = √3
Now ,
As per Pythagoras theorem , we have ;
=> h² = p² + b²
=> h² = 1² + (√3)²
=> h² = 1 + 3
=> h² = 4
=> h = √4
=> h = 2
Thus ,
• sinθ = p/h = 1/2
• cosθ = b/h = √3/2
Alternative method :
We have ,
=> √3•tanθ = 1
=> tanθ = 1/√3
=> tanθ = tan30°
=> θ = 30°
Thus ,
• sinθ = sin30° = 1/2
• cosθ = cos30° = √3/2
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