Question

if 3a+2b+4c= 26, 4a+6b+2c=48 then a+b+c = ?

Answer 1

3a + 2b +4c =26 and 6b + 4a +2c= 48

Divide the second equation by 2,

3b+2a+c=24

Add this to first equation

5a+5b+5c=50

a+b+c=10

Answer 2

3a+2b+4c=26.....(1)

4a+6b+2c=48.....(2)
3×(2)=12a+6b+12c=26×3
4×(1)=12a+8b+16c=48×3