Question

IF 3a+5b+4c=0 show that 27a3+125b3+64c3=180abc

Answer 1

By using the formula ,

a3+ b3+ c3= 3abc, where a+b+c= 0.

then,

(3a)3+ (5b)3 +(4c)3 = 3*3a*5b*4c

= 27a3 + 125b3+ 64c3= 180abc

Hence proved.

Answer 2

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