If -3and2 are the roots of the quadratic equations (x)2 -(p+2)x- q=0 find p and q
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eq 1 : when x= -3,
(-3)2-(p+2)(-3)-q= 0
9-(-3p-6)-q= 0
3p+6-q=-9
3p-q= -15
eq 2 : when x= 2
(2)2-(p+2)2-q= 0
4-2p-4-q=0
-2p-q= 0
eq 1 - eq 2
3p-q+2p+q= -15 -0
3p=-15
p= -5 (ans)
-2p-q=0
-2(-5)-q= 0
-q= -10
q= 10 (ans)
(-3)2-(p+2)(-3)-q= 0
9-(-3p-6)-q= 0
3p+6-q=-9
3p-q= -15
eq 2 : when x= 2
(2)2-(p+2)2-q= 0
4-2p-4-q=0
-2p-q= 0
eq 1 - eq 2
3p-q+2p+q= -15 -0
3p=-15
p= -5 (ans)
-2p-q=0
-2(-5)-q= 0
-q= -10
q= 10 (ans)
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