Question

If Ā=3i + j + 2k and B = 2i -2j+ 4k then value of |Ā×B| will be​

Answer 1

Explanation:

a

=3

i

^

+

j

^

−2

k

^

=> ∣

a

∣=

14

b

=−

i

^

+3

j

^

+4

k

^

=> ∣

b

∣=

26

c

=4

i

^

−2

j

^

−6

k

^

=> ∣

c

∣=

56

Angle between vector a and c =∠B

=> cosB=(

14

+

56

−

26

)/(2

14

56

)=

14

56

22

Length of BM =BA/2=

14

Length of BC =

14

cosB=

14

56

22

By cosine law:

CM

2

=

14

2

+

14

2

−2

14

14

14

56

22

=6

CM=

6

Answer 2

Answer:

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Explanation:

Length of BM =BA/2= 14

Length of BC = 14

cosB= 145622

By cosine law:

CM 2 = 14

2 + 142 −2 14141456

22 =6

CM= 6

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