If Ā=3i + j + 2k and B = 2i -2j+ 4k then value of |Ā×B| will be
Answers
Answered by
2
Explanation:
a
=3
i
^
+
j
^
−2
k
^
=> ∣
a
∣=
14
b
=−
i
^
+3
j
^
+4
k
^
=> ∣
b
∣=
26
c
=4
i
^
−2
j
^
−6
k
^
=> ∣
c
∣=
56
Angle between vector a and c =∠B
=> cosB=(
14
+
56
−
26
)/(2
14
56
)=
14
56
22
Length of BM =BA/2=
14
Length of BC =
14
cosB=
14
56
22
By cosine law:
CM
2
=
14
2
+
14
2
−2
14
14
14
56
22
=6
CM=
6
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Answered by
5
Answer:
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Explanation:
Length of BM =BA/2= 14
Length of BC = 14
cosB= 145622
By cosine law:
CM 2 = 14
2 + 142 −2 14141456
22 =6
CM= 6
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