Question

if 3tan theta=5,then 3sin theta-5cos theta/3sin theta+5cos theta is equal to​

Answer 1

3 tanФ =  5

tanФ = 5\2

sinФ \ cos Ф = 5/2

sinФ = 5    cosФ = 2

3 sinФ - 5 cosФ = 3*5 - 5*3 = 15 - 15 = 0

3 sinФ + 5 cosФ = 3*5 + 5*3 = 15 + 15 = 30

o\30 = 0

NOT SURE.........................................................................

Answer 2

Answer:

Required value of the given expression is 0.

Step-by-step explanation:

$\implies \dfrac{3 \sin( \alpha ) - 5 \cos( \alpha ) }{3 \sin( \alpha ) + 5 \cos( \alpha ) } \\ \\ \\ \implies \dfrac{ \dfrac{3 \sin( \alpha ) - 5 \cos( \alpha ) }{ \cos( \alpha ) } }{ \dfrac{3 \sin( \alpha ) + 5 \cos( \alpha ) }{ \cos( \alpha ) } } \\ \\ \\ \implies \dfrac{3 \dfrac{ \sin( \alpha ) }{ \cos( \alpha ) } - 5 \dfrac{ \cos( \alpha ) }{ \cos( \alpha ) } }{3 \dfrac{ \sin( \alpha ) }{ \cos( \alpha ) } + 5 \dfrac{ \cos( \alpha ) }{ \cos( \alpha ) } } \\ \\ \\ \implies \dfrac{3 \tan( \alpha ) - 5}{3 \tan( \alpha ) + 5 }$

Given, 3 tan$\alpha$ = 5

= > ( 5 - 5 ) / ( 5 + 5 )

= > 0

Hence the required value of the given expression is 0.

*Theta is written as alpha