Question

if 3tanA=4 show that 4cosA-sinA/2-cosA+sinA=4/5

Answer 1

simply take cos A as common factor both in the numerator and denominator cos A will get cancelled and you have (4 - tan A) / (2 +tan A) Because sin A /cos A = tan A Now plug given value of tan A So (4 - 4/3) / (2 + 4/3) = (8/3) / (10/3) Cancelling 3 you have 8/10 and simplified into 4/5. You got it

Answer 2

Answer:

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