if 3x-2y=11, xy=12 find 27x cube - 8y cube
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27x³ -8y³
= (3x)³ - (2y)³
= (3x-2y){(3x)²+(3x)(2y)+(2y)²
=11 {9x²+6xy+4y²}
=11(9x²+6×12+4y²)
=11(9x²+72+4y²)
=99x²+792+44y²
by - Sudhanshu Singh
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