Question

Ten years ago father was twelve times old as his sons and after ten years father will be twice as old as his sons find their present age of father( with step by step explanation )​

Answer 1

Step-by-step explanation: let the age of father be x yrs.

and let his son age be y yrs

ATQ, 10 yrs ago,

x-10= 12(y-10)

x-10=12y-120

x-12y= -110-------------eq 1

also, x+10= 2(y+10)

x+10= 2y+20

x-2y=10-------------------eq 2

by elimination,

x    -12y= -110

x    -2y=    10

(-)   (+)      (-)

  -10y = -120

y= 12 yrs

therefore father's age = x -2(12)= 10

x= 10+24

x= 34 yrs