if 3x-4/x=4,find 27x³-64/x³
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identity
=> (a³+b³ ) = (a+b)(a²+ab+b²)
according to question
3x - 4/x = 4 ......(1)
take both side square
=> 9x² + 16/x² - 24 = 16
=> 9x² + 16/x² = 40 ......(2)
then
=> 27x³ - 64/x³
= (3x)³ - (4/x)³
= (3x + 4/x) (9x² + 16/x² + 12)
put the value from equation (1) & (2)
= 4 (40 +12)
= 4×52
= 208
,,hope it can help you ,,.......→✌
=> (a³+b³ ) = (a+b)(a²+ab+b²)
according to question
3x - 4/x = 4 ......(1)
take both side square
=> 9x² + 16/x² - 24 = 16
=> 9x² + 16/x² = 40 ......(2)
then
=> 27x³ - 64/x³
= (3x)³ - (4/x)³
= (3x + 4/x) (9x² + 16/x² + 12)
put the value from equation (1) & (2)
= 4 (40 +12)
= 4×52
= 208
,,hope it can help you ,,.......→✌
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