If 3x-4y=10 and xy=-1,find the value of 9xsq +16ysq
Answers
Answered by
6
9x²+16y²
=(3x)²+(4y)²
=(3x-4y)²+2*3x*4y
=(10)²+24*-1 [given]
=100+(-24)
=100-24
=76
hope this answer helps you
=(3x)²+(4y)²
=(3x-4y)²+2*3x*4y
=(10)²+24*-1 [given]
=100+(-24)
=100-24
=76
hope this answer helps you
Answered by
10
3x-4y=10
⇒(3x-4y)² = 10² (squaring boths sides)
⇒9x² + 16y² -24xy = 100
⇒9x² + 16y² = 100 + 24xy
⇒9x² + 16y² = 100 - 24 [xy = -1, given]
⇒9x² + 16y² = 76
∴9x² + 16y² = 76
I hope this helps you ^_^
⇒(3x-4y)² = 10² (squaring boths sides)
⇒9x² + 16y² -24xy = 100
⇒9x² + 16y² = 100 + 24xy
⇒9x² + 16y² = 100 - 24 [xy = -1, given]
⇒9x² + 16y² = 76
∴9x² + 16y² = 76
I hope this helps you ^_^
Similar questions
Math,
7 months ago
Social Sciences,
7 months ago
Hindi,
1 year ago
Science,
1 year ago
Biology,
1 year ago
Social Sciences,
1 year ago