Math, asked by amalbino159, 1 year ago

If 3x-5y/5z+3y=x+5z/y-5x=y-z/x-z then show that every ratio =x/y

Answers

Answered by amitnrw
8

Answer:

3x-5y/5z+3y=x+5z/y-5x=y-z/x-z = x/y

Step-by-step explanation:

3x-5y/5z+3y=x+5z/y-5x=y-z/x-z

multiplying numerator & denominator of last term by 5

= 3x-5y/5z+3y=x+5z/y-5x=5y-5z/5x-5z

Now on Applying equal ratio theorem  

a/b = c/d  = e/f = (a + b + c)/(d + e + f)

= (3x - 5y + x + 5z + 5y - 5z)/(5z + 3y + y - 5x + 5x - 5z)

= 4x/4y

Cancelling 4

= x/y

Hence

3x-5y/5z+3y=x+5z/y-5x=y-z/x-z = x/y

Similar questions