Question

If 4/5,a,2 are three consecutive terms of an A.P.,then find the value of a.

Answer 1

4/5,a,2
q=q1=4/5 ; q2=a ; q3=2
q3=2
q+2d=2
(4/5)+2d=2
2d=2-(4/5)
2d=(10-4)/5
2d=6/5
d=6/(5·2)
d=3/5
q2=a=q+d
        =(4/5)+(3/5)
        =(4+3)/5
        =7/5