If 4/5 of a cistern is filled in 1 min , how much more time will be required to fill the rest of it
Answers
Answered by
5
Hy...
Friend........ .
======================
Here your solution
========================
Let the cistern fill fully in x minutes.
In 1 minute ====== 4/5 cistern
In x minutes ====== 1 cistern
USING PROPORTIONALITY METHOD,
1 : 4/5 :: x : 1
Product of means = Product of extremes
1 × 1 = 4/5 × x
1 = 4/5 of x
=> x = 5/4 minutes
1 minute = 60 seconds
=> 5/4 × 60
=> 75 seconds
>>>>>>>>>>>>>>>>>>>>>>>>>>>>
ANSWER = 75 seconds OR 1 minute 15 seconds
>>>>>>>>>>>>>>>>>>>>>>>>>>>
Thankyou
Friend........ .
======================
Here your solution
========================
Let the cistern fill fully in x minutes.
In 1 minute ====== 4/5 cistern
In x minutes ====== 1 cistern
USING PROPORTIONALITY METHOD,
1 : 4/5 :: x : 1
Product of means = Product of extremes
1 × 1 = 4/5 × x
1 = 4/5 of x
=> x = 5/4 minutes
1 minute = 60 seconds
=> 5/4 × 60
=> 75 seconds
>>>>>>>>>>>>>>>>>>>>>>>>>>>>
ANSWER = 75 seconds OR 1 minute 15 seconds
>>>>>>>>>>>>>>>>>>>>>>>>>>>
Thankyou
deepti33:
Thanks
Answered by
3
Heyy!!
Let the cistern fill fully in x minutes.
In 1 min=4/5 cistern
In x min= 1 cistern
USING PROPORTIONALITY METHOD,
1 : 4/5 :: x : 1
Product of means = Product of extremes
1 × 1 = 4/5 × x
1 = 4/5 of x
=> x = 5/4 minutes
1 minute = 60 seconds
=> 5/4 × 60
=> 75 seconds
✌Hope it helps❤♥
Let the cistern fill fully in x minutes.
In 1 min=4/5 cistern
In x min= 1 cistern
USING PROPORTIONALITY METHOD,
1 : 4/5 :: x : 1
Product of means = Product of extremes
1 × 1 = 4/5 × x
1 = 4/5 of x
=> x = 5/4 minutes
1 minute = 60 seconds
=> 5/4 × 60
=> 75 seconds
✌Hope it helps❤♥
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