Question

If 4/7 of a piece of work is completed in 7/4 days, in how many days can rest of the work be completed ?(a) 7/3 days(b)3/7 days(c) 21/16 days(d) 16/21 days​

Answer 1

Given :-

• (4/7) of work completed in = 7/4 days.

To Find :-

• in how many days can rest of the work be completed ?

Solution :-

we know That, Total work is 1.

→ work done = (4/7) of work.

→ work Left to be done = 1 - (4/7) = (7-4)/7 = (3/7) Piece of work.

Therefore,

→ (4/7) of work completed in = 7/4 days.

→ 1 unit of work completed in = (7/4) /(7/4) = (7/4) * (7/4) = (49/16) Days.

→ (3/7) of work completed in = (49/16) * (3/7) = (7*3)/16 = (21/16) Days. (Option C) (Ans.)

Hence, rest of the work be completed in (21/16) Days.

Answer 2

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$\huge\tt{GIVEN:}$

• 4/7 of a piece of work is completed in 7/4 days

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$\huge\tt{TO~FIND:}$

• in how many days can rest of the work be completed ?

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$\huge\tt{SOLUTION:}$

Let the whole work be 1

Than,

↪ Remaining work = {1-(4/7)}

↪Remaining work = {(7-4)/7}

↪Remaining work = (3/7)

↪(4/7) unit of work is done in = 7/4 days

↪1 unit of work completed in = 7/4 × 7/4

↪1 unit of work completed in = (49/16) or 3.0625 Days

↪(3/7) units of work completed in = (49/16 × 3/7)

↪(3/7) units of work completed in = (7×3)/16

↪(3/7) units of work completed in = (21/16) or 1.3125 Days or Option (C)

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