If -4 is a root of the equation x2+px-4=0 and equation 2x2+px+k=0 has equal roots find k and p
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Answer:
k = -20
Explanation:
i) It is given that -4 is a root
of the quadratic equation
x²+px-4=0,
=> (-4)²+p(-4)-4 = 0
=> 16-4p-4 = 0
=> 12-4p = 0
Divide each term by 4 , we get
=> 3-p = 0
=> p = 3 ------(1)
ii ) -4 is a root of one root
of 2x²+px+k = 0
=> 2(-4)²+p(-4)+k = 0
=> 32-4p+k = 0
put p=3 , we get
=> 32-4×3 +k = 0
=> 32 -12 + k = 0
=> 20 + k = 0
=> k = -20
Therefore,
k = -20
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