Math, asked by yugaansh37, 11 months ago

If 4^log(2) 2x = 36 find x

Answers

Answered by vigneshking
3

 {4}^{ log_{2}(2x) }  = 36
 log_{2}(2x)  =  log_{4}(36)
 log_{2}(2x)  =  log_{2}( \sqrt{36} )
2x =  \sqrt{36}
x =  \frac{2 \sqrt{9} }{2}
x  =   \sqrt{9}
Answered by Jeevaking
2
the value of x is 3.....
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