Question

Three concentric spherical shells have radii a, b and c (a < b < c) and have surface charge densities

Answer 1

Answer:

Three concentric spherical shells have radii a,b and c(a<b<c) and have surface charge densities σ,-sigam and σ respectively. If VA,VB and VC denote the potentials of the three shells, then for c=q+b, we have.

Explanation:

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Answer 2

Answer:

Va=Vc≠Vb

Explaination:

Method 1 (quick answer):-

from the formula

Q= σA

i.e. σ= Q/A

also A∝ r

So, σ∝Q/r --(1)

Now in equation of potential:

V=KQ/r

from Eq. --(1)

V∝Q/r => V∝σ --(2)

Given: charge density for A: σ, B: -σ & C: σ

So, in Eq. --(2)

Va= σ, Vb= -σ & Vc=σ (removed proportionality constant 'K' bcs it's value is same in all three cases)

also, σ> -σ or say σ≠ -σ

therefore; Va=Vc>Vb or Va=Vc≠Vb

Method 2 (Derivation):-

see image