Question

if 45-[28- {37-(15-x)}] = 58 then x =

Answer 1

$\huge{\bold{\boxed{\boxed{Answer:-}}}}$

We have to remove bracket first

$\implies{\mathsf{45-28-37-15-x=58}}$

$\implies{\mathsf{-35-x=58}}$

$\implies{\mathsf{-x=58+35}}$

$\implies{\mathsf{x=-23}}$

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Answer 2

The correct answer is "x = -93".

Explanation:

$The \ given \ expression \ is:\\\\45-[28-{37-(15-x)}]=58\\\\On \ evaluating \ the \ above \ expression \ is:\\\\45-28-37-15-x=58\\\\45-65-15-x=58\\\\45-80-x=58\\\\-35-x=58\\\\On \ adding \ "35" both \ sides,we \ get\\\\-35-x+35=58+35\\\\-x=93\\\\x=-93$

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