Math, asked by Lavinkumarthakur, 1 year ago

If 49a^2-b=(7a+1\4)(7a-1\4) then find the value of b

Answers

Answered by ArchitectSethRollins
3
Hi friend
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Your answer
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49a² - b = (7a + 1/4)(7a - 1/4)

(7a)² - (1/4)² = 49a² - b

=> 49a² - 1/16 = 49a² - b

So, after equalising LHS and RHS, we have ,

b = 1/16

HOPE IT HELPS

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