Math, asked by Nehu11, 1 year ago

If 4m+8,2m²+3m+6,3m²+4m+4are three consecutive terms of an AP. Find m.

Answers

Answered by TheLifeRacer
47
heya friends !!!!

let three term in an AP.

4m+8,2m^2+3m+6,3m^2+4m+4

As you know that if term are in a AP then it s common difference are equal so.

d=t2-t1=2m^2+3m+6-4m-8

d=2m^2-m-2---------1)

and again......similarly

d=t3-t2.

d=3m^2+4m+4-2m^2-3m-6

d=m^2+m-2 ------2)

from 1) and 2)

we get,

m^2+m-2=2m^2-m-2

=)m^2-2m=0

=)m(m-2)=0

m=0 ---1)

and m=2,

hope it help you ☺1

@rajukumar☺☺

Nehu11: thnkuu
Answered by yashahuja312
1

heya friends !!!!

let three term in an AP.

4m+8,2m^2+3m+6,3m^2+4m+4

As you know that if term are in a AP then it s common difference are equal so.

d=t2-t1=2m^2+3m+6-4m-8

d=2m^2-m-2---------1)

and again......similarly

d=t3-t2.

d=3m^2+4m+4-2m^2-3m-6

d=m^2+m-2 ------2)

from 1) and 2)

we get,

m^2+m-2=2m^2-m-2

=)m^2-2m=0

=)m(m-2)=0

m=0 ---1)

and m=2,

hope it help you ☺1

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