Question

if 4square+ysquare=20xy,than prove that 2log(2x-) =4log2+logx+logy

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

4x^2+y^2=20xy

Add -4xy on both sides

4x^2-y^2-4xy=20xy-4xy

It is in the form of (a-b)^2

(2x-y)^2=16xy

Add log on both sides

Log (2x-y)^2=log 16xy

2log (2x-y)=log16+logx+log

2log(2x-y)=log2^4+logx+log

2log (2x-y)=4log2+logx+logy