Question

if 55% of 1000÷60% of 2000=K:2K+2,then find the sum of digits of K

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\huge\red{Hi\: Friend}$

Here is your answer

55% of 1000
$= \frac{55}{100} \times 1000 \\ = 550$
60% of 2000
$= \frac{60}{100} \times 2000 \\ = 1200$
Now
ATQ
$\frac{550}{1200} = \frac{k}{2k + 2} \\ \frac{11}{24} = \frac{k}{2k + 2} \\ 11(2k + 2) = 24k \\ 22k + 22 = 24k \\ 24k - 22k = 22 \\ 2k = 22 \\ k = \frac{22}{2} \\ k = 11$
Sum of digits of K is = 1+1
= 2

$<marquee>Hope it helps you$