if 5x is a perfect cube,then the least number of '5's that must be contained in the prime factorization of x is
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7
Answer:
If '5x' is a perfect cube, then the least number of '5's that must be contained in the prime factorization of x is 2 i.e. two more 5s must be obtained in x to make 5x a perfect cube.
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Answered by
5
Answer:
3 fives must be present at least
Explanation:
If 5x is a perfect cube then the least value of x to make it a perfect cube is 25 as 125 is a perfect cube.
125 = 5*5*5
Thus, the least number of 5s in the prime factorisation is 3
Hope this helps! If it does, feel free to mark this answer brainliest! Thanks :D
3 fives must be present at least
Explanation:
If 5x is a perfect cube then the least value of x to make it a perfect cube is 25 as 125 is a perfect cube.
125 = 5*5*5
Thus, the least number of 5s in the prime factorisation is 3
Hope this helps! If it does, feel free to mark this answer brainliest! Thanks :D
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