Math, asked by dudiajaykumar23, 10 months ago

if 5x is a perfect cube,then the least number of '5's that must be contained in the prime factorization of x is​

Answers

Answered by Pragya3918red
7

Answer:

If '5x' is a perfect cube, then the least number of '5's that must be contained in the prime factorization of x is 2 i.e. two more 5s must be obtained in x to make 5x a perfect cube.

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Answered by shouryavirjain
5
Answer:

3 fives must be present at least

Explanation:

If 5x is a perfect cube then the least value of x to make it a perfect cube is 25 as 125 is a perfect cube.

125 = 5*5*5

Thus, the least number of 5s in the prime factorisation is 3

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