Question

If 64ˣ = 1/256ʸ Show that 3x + 4y = 0​

Answer 1

Step-by-step explanation:

${64}^{x} = {256}^{ - y} \\ {2}^{6x} = {2}^{ - 8y} \\ both \: have \: same \: power \: compare \\ = > 6x = - 8y \\ = > 6x + 8y = 0 \\ = > 3x + 4y = 0$

Answer 2

64x=1/256y

→2^6x= 256^-y

→ 2^6x=2^-8y

Since,as a index rule

a^b=a ^c^ b=c as they have same power,

6x= -8y

6x+8y=0

3x+4y=0