If 7 times a7 is equal to 11 times a11, then find the 18th term
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Hey there !!
Given :-
→ 7( a₇ ) = 11( a₁₁ ) .
To find :-
→ a₁₈ = ? .
Solution :-
We have,
⇒ 7( a₇ ) = 11( a₁₁ ) .
⇒ 7( a + 6d ) = 11 ( a + 10d ) .
⇒ 7a + 42d = 11a + 110d .
⇒ 42d - 110d = 11a - 7a .
⇒ - 68d = 4a .
⇒ 4a = -68d .
⇒ 4a + 68d = 0 .
⇒ 4( a + 17d ) = 0 .
⇒ a + 17d = 0/4 .
⇒ a + 17d = 0 .
⇒ a + ( 18 - 1 )d = 0 .
∴ a₁₈ = 0 .
Hence, 18th term of the AP is 0 .
THANKS.
#BeBrainly .
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