if 7th term of an ap is equal to 11 times its 11th term, then its 18th term will be?
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Let 1st term & common difference of the A.P. be respectively a & d. according to question
7 ( a + 6d) = 11 ( a + 10 d)
⇒11a + 110 d = 7a + 42 d
⇒ 4a + 68 d = 0 ⇒ 4(a + 17 d) = 0
⇒ a + 17d = 0
⇒ 18th term⇒ a + 17 d = 0
7 ( a + 6d) = 11 ( a + 10 d)
⇒11a + 110 d = 7a + 42 d
⇒ 4a + 68 d = 0 ⇒ 4(a + 17 d) = 0
⇒ a + 17d = 0
⇒ 18th term⇒ a + 17 d = 0
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the answer is 0.......
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