if 8 a root of the equation x2 - 10x + k then the value of k
Answers
Answered by
101
Hi ☺☺
Your Answer...
Let, p(x) = x²-10x+k
since, 8 is the root of p(x)
•°• p(8) = 0
8²-10(8)+k = 0
64-80+k = 0
-16+k = 0
=> k = 16 .
☺☺
Your Answer...
Let, p(x) = x²-10x+k
since, 8 is the root of p(x)
•°• p(8) = 0
8²-10(8)+k = 0
64-80+k = 0
-16+k = 0
=> k = 16 .
☺☺
Answered by
11
8^2-80+k=0
k=80-64
k=16
k=80-64
k=16
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