Question

if 8 types are required to fill a tank in one hour and 40 minutes . How long will it take if only 7 pipes of the same type are used . solve using inverse proportion and tabulate the data .

Answer 1

Answer:

$\boxed{1\frac{19}{21}hrs}$

Step-by-step explanation:

8 types of pipe fill it in 1 hour 40 minutes

∴ 8 types fill in 60 + 40 = 100 minutes

∴ 1 type fill in 100 × 8 = 800 minutes

∴ 7 type fills in 800/7 minutes

800/7 minute = 800/420 hours

= 80/42

= 40/21 hours

= $1\frac{19}{21}$

Inverse proportion

Time taken ∝ 1 / number of pipes .

Tabular form

Number of pipes             Time

8                                        100 min

7                                        700 min

1                                         800 min