Question

If 8x+4, 6x-2,2x+7 is an ap howto find 49th term

Answer 1

they are in AP

t(2)-t(1) = t(3)-t(2)

6x-2-8x-4 = 2x+7-6x+2

-2x-6 = -4x+9

2x = 15

x = 15/2

The three terms are

64, 43, 22

a= 64 d = -21

t(49) = a + 48d

= 64 - 48(21)

= 64 - 1008

= - 944

Answer 2

Hey there!

Common difference is same between every two consecutive terms ,so

6x - 2 - ( 8x + 4 ) = 2x + 7 - ( 6x - 2 )

6x - 2 - 8x - 4 = 2x + 7 - 6x + 2

-2x - 6 = -4x + 9

-2x + 4x = 9 + 6

2x = 15

x = 15/2 .

Now,
First term = 8(15/2)+4 = 64
Second term = 43

Common difference = 43 - 64 = -21

49 term = a + 48d = 64 + 48 ( -21 ) = 64 - 1008 = -944

Hope helped!