If 8x+4, 6x-2,2x+7 is an ap howto find 49th term
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Answered by
0
they are in AP
t(2)-t(1) = t(3)-t(2)
6x-2-8x-4 = 2x+7-6x+2
-2x-6 = -4x+9
2x = 15
x = 15/2
The three terms are
64, 43, 22
a= 64 d = -21
t(49) = a + 48d
= 64 - 48(21)
= 64 - 1008
= - 944
t(2)-t(1) = t(3)-t(2)
6x-2-8x-4 = 2x+7-6x+2
-2x-6 = -4x+9
2x = 15
x = 15/2
The three terms are
64, 43, 22
a= 64 d = -21
t(49) = a + 48d
= 64 - 48(21)
= 64 - 1008
= - 944
Answered by
3
Hey there!
Common difference is same between every two consecutive terms ,so
6x - 2 - ( 8x + 4 ) = 2x + 7 - ( 6x - 2 )
6x - 2 - 8x - 4 = 2x + 7 - 6x + 2
-2x - 6 = -4x + 9
-2x + 4x = 9 + 6
2x = 15
x = 15/2 .
Now,
First term = 8(15/2)+4 = 64
Second term = 43
Common difference = 43 - 64 = -21
49 term = a + 48d = 64 + 48 ( -21 ) = 64 - 1008 = -944
Hope helped!
Common difference is same between every two consecutive terms ,so
6x - 2 - ( 8x + 4 ) = 2x + 7 - ( 6x - 2 )
6x - 2 - 8x - 4 = 2x + 7 - 6x + 2
-2x - 6 = -4x + 9
-2x + 4x = 9 + 6
2x = 15
x = 15/2 .
Now,
First term = 8(15/2)+4 = 64
Second term = 43
Common difference = 43 - 64 = -21
49 term = a + 48d = 64 + 48 ( -21 ) = 64 - 1008 = -944
Hope helped!
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