Question

If 90g of pure water is obtained through 80 g of oxygen and X g of hydrogen.(a) find the value of X. (b) which chemical law is illustrated by this statement?

Answer 1

a) The value of X is 10g.

80g of O2+Xg of H2→90g of H20

b) By Law of Conservation of Mass,
both reactants' side and products' side should have equal mass as atoms can neither be created nor destroyed during the course of a chemical change. That is why we need 10g of Hydrogen with 80g of Oxygen to get 90g of water.

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Answer 2

Answer:80g of O2+Xg of H2→90g of H20

b) By Law of Conservation of Mass,

both reactants' side and products' side should have equal mass as atoms can neither be created nor destroyed during the course of a chemical change. That is why we need 10g of Hydrogen with 80g of Oxygen to get 90g of water.

Explanation: