if 9th term of an A.P is (2n+1)what is the sum of its three term
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a9-2n+1
a+8d=2n+1
a=2n+1-8d
s3=n/2(2a+(n-1)d)
=n/2(2*(2n+1-8d)+dn-d)
n/2(4n+2-16d+dn-d)
n/2(4n+2-17d+dn)
Answer..
a+8d=2n+1
a=2n+1-8d
s3=n/2(2a+(n-1)d)
=n/2(2*(2n+1-8d)+dn-d)
n/2(4n+2-16d+dn-d)
n/2(4n+2-17d+dn)
Answer..
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Answer:
Given :
nth term = 2 n + 1
= > a₁ = 2 + 1
= 3
= > a₂ = 4 + 1
= 5
d = a₂ - a₁
= > 5 - 3
= 2
Sₙ = n / 2 [ 2 a + ( n - 1 ) d ]
S₃ = 3 / 2 [ 6 + 2 × 2 ]
S₃ = 3 / 2 [ 10 ]
S₃ = 3 × 5
S₃ = 15 .
Therefore , sum of first three numbers is 15 .
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