If A (1,-1),B (0,4),C (-5,3) are vertices of a triangle then find the slope of each side.
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If two points (x₁ ,y₁) and (x₂, y₂) are given then of line joining the points is given by (y₂ - y₁)/(x₂ - x₁).
A ≡ (1, -1) , B ≡ (0, 4) and C ≡ ( -5,3)
Slope of side AB = (4 + 1)/(0 - 1) = -5
Slope of side BC = (3 - 4)/(-5 - 0) = -1/-5 = 1/5
slope of side CA = (-1 - 3)/(1 + 5) = -4/6 = -2/3
A ≡ (1, -1) , B ≡ (0, 4) and C ≡ ( -5,3)
Slope of side AB = (4 + 1)/(0 - 1) = -5
Slope of side BC = (3 - 4)/(-5 - 0) = -1/-5 = 1/5
slope of side CA = (-1 - 3)/(1 + 5) = -4/6 = -2/3
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