If a + 1/ 16, then find the value of a^2 +1/a^2?
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Correct question;
If ( a + 1/a) = 16 , then find the value of
a^2 + 1/a^2.
Note,
(a + b)^2 = a^2 + b^2 + 2•a•b
we can use this identity to find the value of a^2 + 1/a^2
Now;
=> (a+1/a)^2 = a^2 + (1/a)^2 + 2•a•(1/a)
=> (16)^2 = a^2 + 1/a^2 + 2
=> 256 = a^2 + 1/a^2 + 2
=> a^2 + 1/a^2 = 256 - 2
=> a^2 + 1/a^2 = 254
Thus, the required value of a^2 + 1/a^2 is 254.
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