If a=1/7-4√3 and b=1/7+4√3, find a³+b³
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Answer is 48
a^3 + b^3 = (a+b)(a^2-ab+b^2)
so when we substitute the value the answer would be 48.
a^3 + b^3 = (a+b)(a^2-ab+b^2)
so when we substitute the value the answer would be 48.
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