if a+1/a=3 then a^4+1/a^4=?
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(a+1/a)power4 is 81.
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Answer:
Note:
(A+B)^2 = A^2 + B^2 + 2•A•B
Given:
a +1/a = 3
To find:
a^4 + 1/a^4 = ?
Solution:
Here, we have;
a +1/a = 3 --------(1)
Also, we know that;
=> (a+1/a)^2 = a^2 +(1/a)^2 +2•a•(1/a)
=> (3)^2 = a^2 +1/a^2 + 2 {using eq-1}
=> 9 = a^2 + 1/a^2 + 2
=> a^2 + 1/a^2 = 9 - 2
=> a^2 + 1/a^2 = 7 ---------(2)
Again;
=> (a^2 +1/a^2)^2 = (a^2)^2 + (1/a^2)^2
+ 2•(a^2)•(1/a^2)
=> (7)^2 = a^4 +1/a^4 + 2 {using eq-2}
=> 49 = a^4 + 1/a^4 + 2
=> a^4 + 1/a^4 = 49 - 2
=> a^4 + 1/a^4 = 47
Hence,
The required value of a^4 + 1/a^4 is;
47.
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