Math, asked by vanshijivrajanitcj, 11 months ago

if a-1/a=√5 then find the values of a + 1/ a and a³ + 1/a³

Answers

Answered by pansumantarkm
4

Step-by-step explanation:

a -  \frac{1}{a}  =  \sqrt{5}  \\  =  > on \: squaring \: both \: sides \\  =  >  {(a -  \frac{1}{a}) }^{2}  = 5 \\  \\  =  >  {(a + \frac{1}{a} )}^{2}  - 4 \times  \frac{1}{a}  \times a = 5 \\  \\  =  > {(a +  \frac{1}{a})}^{2} = 5 + 4 \\  \\  =  >  {(a +  \frac{1}{a})}^{2} = 9 \\  \\  =  > a +  \frac{1}{a}  =  \binom{ + }{ - } 3 \\

Now,

a +  \frac{1}{a}  =  \binom{ + }{ - } 3 \\  \\  =  >  {(a +  \frac{1}{a} )}^{3}  =  \binom{ + }{ - } 27 \\  \\  =  >  {a}^{3}  +  \frac{1}{ {a}^{3} }  + 3a \times  \frac{1}{a} (a +  \frac{1}{a} ) =  \binom{ + }{ - } 27 \\  \\  =  >  {a}^{3}  +  \frac{1}{ {a}^{3} }  + 3 \times 3 =  \binom{ + }{ - } 27 \\  \\  =  >  {a}^{3}  +  \frac{1}{ {a}^{3} }  =  \binom{ + }{ - } 27 - 9 \\  \\  =  >  {a}^{3}  +  \frac{1}{ {a}^{3} }  =  \binom{ +18 }{ -35 }

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Answered by Anonymous
0

Answer:

this is the answer of the question

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