if a+1/a=6 find a- 1/a and a^2- 1/a^2
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Answered by
95
Hi...☺
Here is your answer...✌
GIVEN THAT,
HENCE,
Here is your answer...✌
GIVEN THAT,
HENCE,
sushant2505:
:-)
Answered by
2
Step-by-step explanation:
a+a1=6Squaringbothsidesweget(a+a1)2=62a2+a21+2×a×a1=36a2+a21+2=36a2+a21=34Subtracting2bothsideswegeta2+a21−2=34−2a2+a21−2×a×a1=32(a−a1)2=32(a−a1)=32or−32(a−a1)=42or−42Now,a2−a21=(a+a1)(a−a1)when(a−a1)=42(a2−a21)=6×42=242when(a−a1)=−42(a2−a21)=6×(−42)=−242
HENCE,
\begin{gathered}(a - \frac{1}{a} ) = 4 \sqrt{2} \: \: or \: \: - 4 \sqrt{2} \\ \\ and \\ \\ (a {}^{2} - \frac{1}{a {}^{2} } ) = 24 \sqrt{2} \: \: or \: \: - 24 \sqrt{2} \end{gathered}(a−a1)=42or−42and(a2−a21)=242or−242
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