Question

if a^2+b^2=34andab=15,find a+b,a-b​

Answer 1

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_Given _

a^2 + b^2 = 34

ab = 15

_So_ ; By using the formula :

(a + b)^2 = a^2 + b^2 + 2ab

= 34 + 2 × 15

= 64

( a + b ) = √64 = 8

_Again_ ; by using the formula :

(a - b )^2 = a^2 + b^2 - 2ab

= 34 - 2×15

= 4

( a - b ) = √4 = 2

________________________

Hence ,

➡️ (a+b) = 8

➡️ (a - b ) = 2

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Answer 2

Answer:

${a }^{2} + {b }^{2} = 34 \\ {(a + b) }^{2} - 2ab = 34 \\ {(a + b)}^{2} = 34 + 2ab \\ {(a + b) }^{2} = 34 + 2 \times 15 \\ {(a + b) }^{2} = 34 + 30 \\ {(a + b)}^{2} = 64 \\ a + b = \sqrt{64} \\ a + b = 8 \\ \\ {a}^{2} + {b}^{2} = 34 \\ {(a - b)}^{2} + 2ab = 34 \\ {(a - b) }^{2} = 34 - 2ab \\ {(a - b)}^{2} = 34 - 2 \times 15 \\ {(a - b)}^{2} = 34 - 30 \\ {(a - b)}^{2} = 4 \\ a - b = 2 \\ \\ hope \: \: you \: understand \\ and \: follow \: me$