Question

If a = 2^m and b= 2^m+1, show that 8a^3 ÷ b^2 = 2^m+1​

Answer 1

Step-by-step explanation:

it's too hard for me sorry

Answer 2

Answer:

hi i hope this answer is correct

Step-by-step explanation:

Now the lhs oc the equation and solve them

Now take cube a=a^3=2^3m,8a^3=2^*(3m+3)

since 8=2*2*2 and powers add when the base is multiplied same....

b^2=2^*(2m+2)

therefore 8a^3/b^2 =2^(3m+3)/2^(2m+2)

subtract=2^(m+1)

since LHS=RHS Hence proved

thank u