Question

if a = 2^m and b= 2^m+1 , show that 8a^3/b^2 =2^m+1​

Answer 1

Answer:

Hello  there!

Step-by-step explanation:

Take the LHS of the equation and solve it.

take cube of a => a^3 = 2^3m, 8a^3 = 2^(3m+3)   {since 8= 2*2*2, and powers add when multiplied with the same base.

b^2 = 2^(2m + 2)

therefore, 8a^3/b^2 = 2^(3m+3)  / 2^(2m + 2)

                                 = powers will subtract.

                                 = 2^ (m+1)

since LHS= RHS, Hence proved.  (don't forget write at the end !!)

Hope it helps.

Answer 2

Answer:

Take the LHS of the equation and solve it.

take cube of a => a^3 = 2^3m, 8a^3 = 2^(3m+3)   {since 8= 2*2*2, and powers add when multiplied with the same base.

b^2 = 2^(2m + 2)

therefore, 8a^3/b^2 = 2^(3m+3)  / 2^(2m + 2)

                                = powers will subtract.

                                = 2^ (m+1)

since LHS= RHS, Hence proved.

Step-by-step explanation: