Question

if a+2b+3c=0 than prove that a³+8b³+27c³=18abc

Answer 1

If a+b+c=0 then a^3+b^3+c^3=3ABC
then a+2b+3c=0
then. a^3+(2b)^3+(3c)^3=3×a×2b×3c
a^3+8b^3+27c^3=18abc

Answer 2

Refer the attachment for the answer