if a=2x,b=5x-1 and c=x^2-1 find the value of x and angles A and B
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priyabachala:
In triangle right
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let triangle ABC be the triangle and angl a + angle b +angle c =180 degree ___ by aangle some property then put the values of the x and y and solve
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Answer:
Step-by-step explanation:
(x+1)^2 = (5x-1)^2 + (2x)^2
x^2 + 2x +1 = 25x^2 - 10x + 1 + 4x^2 (using the rule (a+b)^2 = a^2 + 2ab +b^2)
29x^2 - x^2 -10x -2x +1 - 1 = 0 (subtracting both sides with x^2 +2x +1
28x^2 -12x = 0
x(28x -12) = 0
x = 0 or x = 12/28 = 3/7 ( since any number times zero is zero either x has to equal zero or 28x-12 = 0)
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