Question

If A = (3.-4) and the mid points of AB, AC are (2, -1), (4, -5) respecitvely then the mid
points of BC is
1) (1, 2)
2) (3,-2)
3) (-1, 2)
4) (0, -3)​

Answer 1

Answer:

Step-by-step explanation:

GIVEN

A=(3,-4)

LET P BE THE MIDPOINT OF AB

by mid point formula

P=(x1+x2/2,y1+y2/2)

(2,-1)=($\frac{x1+x2}{2}$,$\frac{y1+y2}{2}$)

on equating like terms

3+x=4; y-4=-2

x=1;y=2

hence coordinates of B=(1,2)

NOW AGAIN APPLYING SAME PROCESS

WE GET

COORDINATES OF C ARE

C=(5,-6)

NOW MIDPOINT OF BC

COORDINATES OF MIDPOINT OF BC = (3,-2)